如图所示,工人用200N的拉力,在15s的时间内,将重500N的建筑材料提升到6m高的楼顶上,求:

1个回答

  • 解题思路:

    (1)读题并观图可知:

    F

    =

    200

    N

    s

    =

    3

    h

    =

    3

    ×

    6

    m

    =

    18

    m

    W

    =

    F

    s

    =

    200

    N

    ×

    18

    m

    =

    3.6

    ×

    10

    3

    J

    (2)

    G

    =

    500

    N

    h

    =

    6

    m

    W

    =

    G

    h

    =

    500

    N

    ×

    6

    m

    =

    3

    ×

    10

    3

    J

    (3)当不计绳与滑轮组间的摩擦及绳重时,

    (

    G

    +

    G

    )

    =

    "

    3

    F

    "

    G

    =

    "

    3

    F

    "

    G

    =

    3

    ×

    200

    N

    500

    N

    =

    100

    N

    .

    (1)3.6×10 3J (2)83.3% (3)  100N

    <>