Question

D为△ABC的边BC延长线上一点,∠A=96°,∠ABC与∠ACD平分线交于A1,∠A1BC与∠A1CD的平分线交于A2

Answer 1

令∠ABA1=∠1,∠A1BC=∠2,∠ACA1=∠3,∠A1CD=∠4,由等平分线定理知∠1=∠2,∠3=∠4,易知∠3+∠4=96°+∠1+∠2,∠4=∠A1+∠2,则得∠A1=∠4-∠2=96°/2=48°,由此类推,∠A2=48°/2=24°,

∠A3=12°,∠A4=6°,∠A5=3°,

辅助图形你自己画一下吧