这个要用到换底公式:log[a](x)=lnx/lna
所以
log [1.0186/1.0104](1223890000/945610000 )
=ln(1223890000/945610000)/ln(1.0186/1.0104)
=ln(1.294286227937521811)/ln(1.0081155977830562)
=31.9144334
这个要用到换底公式:log[a](x)=lnx/lna
所以
log [1.0186/1.0104](1223890000/945610000 )
=ln(1223890000/945610000)/ln(1.0186/1.0104)
=ln(1.294286227937521811)/ln(1.0081155977830562)
=31.9144334