(1)A(4,0),B(0,3)
(2)由题意得:A(4,0),B(0,3),AC=BC,设OC=x,则BC=OA-0C=4-x,由勾股定理得,x²+3²=(4-x)²解得x=7/8即OC=7/8(3)分三种情形,当BP=BA时,P(-4,0)当AB=AP时,P(-1,0)或P(9,0)当PA=PB时,P点就是C点,P(7/8,0)
(1)A(4,0),B(0,3)
(2)由题意得:A(4,0),B(0,3),AC=BC,设OC=x,则BC=OA-0C=4-x,由勾股定理得,x²+3²=(4-x)²解得x=7/8即OC=7/8(3)分三种情形,当BP=BA时,P(-4,0)当AB=AP时,P(-1,0)或P(9,0)当PA=PB时,P点就是C点,P(7/8,0)