Question

已知两点A(2,2)、B（-2,5）,试在y轴上求一点P,使AP⊥PB,写出P点坐标

Answer 1

设p(0,y)

kAP = (2-y)/(2-0)

kBP = (5-y) = (-2-0)

kAP*kBP = 1或-1

解得 y = 1,y=6

p(0,1) (0,6)