多一个sin(2x+π/6)吧!
f(x)=sin(2x+π/6)+2cos²x
=sin2xcosπ/6+cos2xsinπ/6+1+cos2x
=√3/2sin2x+3/2cos2x+1
=√3(1/2sin2x+√3/2cos2x)+1
=√3sin(2x+π/3)+1
函数最小正周期T=2π/2=π
已知函数f(x)=sin(2x+π/6)+sin（2x+π/6）+2cos²x
2个回答
相关问题
-
已知函数f(x)=sin(2x+π／6)+sin(2x-π／6)+2cos²x
-
已知函数f（x）=sin（2x+π/6)+sin（2x -π/6)+2cos²x
-
已知函数f(x)=sin(x+π/6)+sin(x-π/6)-2cos^2(x/2),x∈[0,π] 求化简函数f(x)
-
已知函数f(χ)=sin(2x+π/6 )+sin(2x- π/6)+cos2x+1(x∈R),
-
已知函数f(x)=sin(x-π/6)+cos(x-π/3)g(x)=2sin²x/2
-
已知函数f(x)=2sin(x+π/6)-2sin(π/2+x) x∈[π/2,π]
-
已知函数f(x)=sin(2x+π/6)+sin(2x-π/6)+2cos²x(x∈R).1,求函数F(x)的
-
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)]
-
已知函数f(x)＝sin(2x+π6)−cos(2x+π3)+2cos2x．
-
已知函数f(x)＝sin(2x+π6)−cos(2x+π3)+2cos2x．