若x^2+2x+y^2-6y+10=0,则x-y
1个回答
x^2+2x+y^2-6y+10=0
(x+1)^2 + (y-3)^2 = 0
x = -1,y = 3
x-y = -1 -3 = -4
相关问题
若x^2+y^2+2x-6y=10=0,则x-y=
1.若x^2+y^2-2x+6y+10=0,则代数式x^2+y^2=____
若x+y+2x-6y+10=0,则x的y次方=
若x^2-2x+y^2+6y+10=0
若4x^2+y^2-4x+6y+10=0,则x^y的值为?
证明:若x^2-y^2+x-5y-6≠0,则x-y≠2.
若x2+y2-6y+4x+13=0,则x2-y2=______.
若(3x+y+6)^2+|x+y+2|=0,则x=
若x2-4x+y2+6y+13=0,则x=______,y=______.
若x*2+y*2-2x-6y+10=0,求(x*2-y*2)/xy=?