Question

已知函数F(x)＝ax＋b sin³x＋1(a,b为常数),且F(5)＝7,则F（－5）＝

Answer 1

F(5)=5a+b(sin5)^3+1 5a+b(sin5)^3+1=7 5a+b(sin5)^3=6

F(-5)=-5a+b(sin-5)^3+1 =-( 5a+b(sin5)^3)+1=-6+1=-5