Question

求此题的详解.最好发图过来.

Answer 1

第一问

x^2+y^2+Dx+Ey+3=0

(x+D/2)^2+(y+E/2)^2=(D^2+E^2)/4-3

故圆心为(-D/2,-E/2)

因为圆心在直线x+y-1=0上,且圆心在第二象限

故-D/2-E/2-1=0,且D>0,E