已知f(x)=sin(x+π/3),若α∈(- π

2个回答

若sinα是方程6x=1-√x的根,试求tan(π-α)tan(2π-α)cos(5π-α)/cos(3π/2+α)的值
已知cos(π/6-α)=1/3,求cos(5π/6+α)sin(2π/3-α)的值
已知f（α）=sin(α−3π)•cos(π+α)cos(2π−α)•sin(−π−α)•sin(3π2−α)
已知f(α)＝sin(α−3π)•cos(2π−α)•sin(−α+3π2)cos(−π−α)•sin(−π−α)
已知函数f(x)=sin(x+π/6),且cosα=根号下3/2,α锐角,求f(α)的值
已知：f(α)＝sin(π2−α)•cos(3π2−α)•tan(5π+α)tan(−α−π)•sin(α−3π)
已知f(α)＝sin(π2+α)+3sin(−π−α)2cos(11π2−α)−cos(5π−α)．
.已知sin（α+π／6）=3／5,π／2＜α+π／6＜π,求sinα
已知sin(π/3 -α)=1/5求sin(2π/3 +α)和cos（7π/6 +α）的值
已知f(阿尔法)=sin(π/2+α)+3sin(-π-α)/2cos(11π/2-α)-cos(5π-α).