|x-2|+|y+1/3|=0,
则x-2=0,y+1/3=0
则x=2,y=-1/3
5xy^2-[2x^2y-（4xy^2-2x^2Y)]
=5xy²-2x²y+4xy²-2x²y
=9xy²-4x²y
=9×2×(-1/3)²-4×2²×(-1/3)
=2+16/3
=22/3
已知|x-2|+|y+1/3|=0,求5xy^2-[2x^2y-（4xy^2-2x^2Y)]的值
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