p = 3a+2b+3c
= k1(a+b)+k2(a-b)+k3c
= (k1+k2)a + (k1-k2)b +k3c
=>
3=k1+k2 (1) and
2=k1-k2 (2) and
3=k3
(1)+(2)
2k1=5
k1=5/2
k2=1/2
p在基底{a+b,a-b,c}坐标 =(5/2,1/2,3)
p = 3a+2b+3c
= k1(a+b)+k2(a-b)+k3c
= (k1+k2)a + (k1-k2)b +k3c
=>
3=k1+k2 (1) and
2=k1-k2 (2) and
3=k3
(1)+(2)
2k1=5
k1=5/2
k2=1/2
p在基底{a+b,a-b,c}坐标 =(5/2,1/2,3)