在一个一个圆中,弧长C=5.79614,弦长L=5.3306,求该圆半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=4
R1=4.114732
R2=4.123376
R3=4.123421
R4=4.123421
R=4.123421
在一个一个圆中,弧长C=5.79614,弦长L=5.3306,求该圆半径R?
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=4
R1=4.114732
R2=4.123376
R3=4.123421
R4=4.123421
R=4.123421