写出来后,a1=a7,a2=a8.
所以a1=a（6n+1） 所以a1≠a2004
若数列an满足a1=1.a2=2,an=an-1/an-2,求a2004
1个回答
相关问题
-
若数列an满足 a1=2011,a2=2012,且An+2=(An+1 +1)/An ,求a2012=?
-
数列an满足a1=2,an+1=an²求an
-
数列an中an+2=an+1-an ,a1=1,a2=5 a2004=
-
数列{an}满足a1=a,an+1=1+1/an.若3/2
-
若数列{An}满足A1=1,A(n+1)=An/(2An + 1)
-
若数列{an}满足：a1=1，an+1=2an．n=1，2，3…．则a1+a2+…+an=______．
-
若数列an满足a1＝1/2.a1+a2+a3+……+an＝n^2an
-
数列an满足a1=2 an+1=an/an+3 求an
-
若数列{an}满足：a1=1，an+1=an+2，则a10=______．
-
数列{an}满足a1=3,a2=6,an+2=an+1-an,求a2008