Question

矩形ABCD中,AB=8,AD=10.

Answer 1

∵△ADE≌△AFE,

∴AF=AD=10,

∴BF=√(AF²-AB²)=6,

①若PA=AF,则PB=FB=6

②若FA=FP=10,则PB=PF-BF=4,

③若PA=PF,设PB=X,则AP=6+X,

由勾股得(6+X)²=X²+8²

解得X=7/3

∴PB=7/3