f(x)=x/(x^2+1)
(1)
f '(x)=[(1+x²)-2x²]/(1+x²)²
=[1-x²]/(1+x²)²≥i0
所以函数f(x)在【0,1】上单调增,
(2)
因为函数单调增;
y(MAX)=f(1)=1/2
y(min)=f(0)=0
f(x)=x/(x^2+1)
(1)
f '(x)=[(1+x²)-2x²]/(1+x²)²
=[1-x²]/(1+x²)²≥i0
所以函数f(x)在【0,1】上单调增,
(2)
因为函数单调增;
y(MAX)=f(1)=1/2
y(min)=f(0)=0