(1)2x 2-3x=2
2x 2-3x-2=0
(x-2)(2x+1)=0,
解得:x 1=2,x 2=-
1
2 ;
(2)(x-1) 2+2x(x-1)=0
(x-1)[(x-1)+2x]=0
(x-1)(3x-1)=0,
解得:x 1=1,x 2=
1
3 .
(1)2x 2-3x=2
2x 2-3x-2=0
(x-2)(2x+1)=0,
解得:x 1=2,x 2=-
1
2 ;
(2)(x-1) 2+2x(x-1)=0
(x-1)[(x-1)+2x]=0
(x-1)(3x-1)=0,
解得:x 1=1,x 2=
1
3 .