Question

已知a*a+4a+1=0,且(a*a*a*a-ma*a+1)/(2a*a*a+ma*a+2a)=3 求m的值拜托各位大神

Answer 1

a*a+4a+1=0；a^2+1=-4a a^4+1+2a^2=(-4a)^2=16a^2 a^4+1=14a^2 2a^3+2a=-8a^2 (a*a*a*a-ma*a+1)/(2a*a*a+ma*a+2a)=3 =(14-m)/(m-8) m=19/2