Question

已知a平方+4a+1=0且2a立方+ma平方+2a分之a平方+ma平方+1等于3,试确定m的值.

Answer 1

a^2=-4a-1

a^3=a^2*a=-4a^2-a=-4(-4a-1)-a=16a+4-a=15a+4

a^4=(a^2)^2=16a^2+8a+1=16(-4a-1)+8a+1=-56a-15

(a^4+ma^2+1)/2a^3+ma^2+2a=3

a^4+ma^2+1=6a^3+3ma^2+6a

2ma^2=-6a^3-6a+a^4+1

-8am-2m=-90a-24-6a-56a-15+1=-152a-38

2m(4a+1)=38(4a+1)

m=19