2asinA=(2a+c)sinB+(2c+b)sinC
有正弦定理得:
2sinAsinA=(2sinA+sinC)sinB+(2sinC+sinB)sinC
2(sinA)^2 = 2sinAsinB+2sinCsinB+2(sinC)^2
(sinA)^2 = sinAsinB+ sinCsinB + (sinC)^2
=sinAsin(A+C)+ sinCsin(A+C) + (sinC)^2
=(sinA)^2cosC+sinCsinAcosA + (sinC)^2
你题抄错没有?
2asinA=(2a+c)sinB+(2c+b)sinC
有正弦定理得:
2sinAsinA=(2sinA+sinC)sinB+(2sinC+sinB)sinC
2(sinA)^2 = 2sinAsinB+2sinCsinB+2(sinC)^2
(sinA)^2 = sinAsinB+ sinCsinB + (sinC)^2
=sinAsin(A+C)+ sinCsin(A+C) + (sinC)^2
=(sinA)^2cosC+sinCsinAcosA + (sinC)^2
你题抄错没有?