((3a +b)的2次方-b的2次方))除以a
=(9a²+6a+b²-b²)除以a →把括号里的第一项(3a+b)²展开
=(9a²+6a)除以a →合并同类项
=3a(3a+2)÷a →提取公因数
=3(3a+2)