Question

已知|x-3y－6|+(x+2y-1)的平方＝0,求x,y的值

Answer 1

|x-3y－6|+(x+2y-1)的平方＝0

x-3y-6=0

x+2y-1=0

即﹛x-3y=6﹙1)

x+2y=1(2)

(2)-(1)得 5y=-5

y=-1

代入（2）得

x-2=1

x=3