B(16,9),O(0,0),设L直线方程为y=ax+b过O点和(3,5)则b=0,5=3a推得y=5/3x,
OB=16-0=16
∵∠ABO=45°,则HB=HA,A=(OH,AH)=(x,5x/3)则H=(x,0)
∴OB=16=OH+HB=x+5x/3,推得x=6,H(6,0),则A(6,10),则AH=10,
∴
B(16,9),O(0,0),设L直线方程为y=ax+b过O点和(3,5)则b=0,5=3a推得y=5/3x,
OB=16-0=16
∵∠ABO=45°,则HB=HA,A=(OH,AH)=(x,5x/3)则H=(x,0)
∴OB=16=OH+HB=x+5x/3,推得x=6,H(6,0),则A(6,10),则AH=10,
∴