已知实数x,y满足x^2+3y^2+6x-12y+21=0,求x,y的值
x^2+3y^2+6x-12y+21=0
即（x+3）^2+3(y-2)^2=0
所以x+3=0,y-2=0
所以x=-3,y=2
已知实数x,y满足x^2+3y^2+6x-12y+21=0,求x,y的值
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