若cos(π+α)=-1/2,3π/2
4个回答
cos(π+α)= sin(-π/2 -α)= -sin(π/2 +α)= -cos(-α)= -cosα= -1/2
则cosα=1/2,
sin(2π-α)=sin(-α)= -sinα
3π/2
相关问题
若sin(α-π)=2cos(2π-α),求[sin(π-α)+5cos(2π-α)]/[3cos(π-α)-sin(-
若sin(π2+α)+cos(α−π2)=75,则sin(3π2+α)+cos(α−3π2)=( )
若cos(π+α)=-1/2,3π/2
(1)化简:sin(2π−α)cos(π+α)cos(3π2+α)cos(13π2−α)cos(π−α)sin(3π−α
sin(3π+α )=1/4,求cos(π+α)/cosα[cos(π+α)-1]+cos(α-2π)/cos(α+2π
若cosα=1/7、α∈(0,π/2)求cos(α+π/3)
若sin(π+α)+cos([π/2]+α)=-m,求cos([3π/2]-α)+2sin(2π+α)的值.
1.若α∈(π/2,π),且3cos2α=sin(π/4-α),则sin2α=?
化简(1)tan(π−α)cos(2π−α)sin(−α+3π2)cos(−α−π)sin(−π−α).
若sin(π/6-α)=1/3 则cos(2π/3+α)=?