2sin(θ+π/3)=1+cos(θ+π/3)
sin(θ+π/3)=(1+cos(θ+π/3))/2 降幂公式逆用
2sin(θ/2+π/6)cos(θ/2+π/6)=[ cos(θ/2+π/6) ]^2 正弦倍角公式
2sin(θ/2+π/6)=cos(θ/2+π/6)
tan(θ/2+π/6)=1/2
( tanθ/2+tanπ/6)/(1-tanθ/2 * tanπ/6) =1/2
tanθ/2 =(3-2根号3)/(6+根号3） 结果你在再算算,思想,方法就这样
若2sin(θ+π/3)=1+cos(θ+π/3),则tanθ/2=_____
2个回答
相关问题
-
cos(π-θ)tan(3π+θ)/sin(π/2+θ)=3/4,则cosθ=?
-
若sinθ+cosθ=√2,则tan（θ+π/3）
-
化简sin(θ−5π)tan(3π−θ)•1tan(θ−3π2)tan(π2−θ)•cos(8π−θ)sin(−θ−4π
-
设f（θ）=2cos(2 π-θ)sin(π2+θ)1tan(π-θ)•cos(3π2-θ)．
-
三角函数计算：若sinθ+cosθ=√2 则tan(θ+π/3)=?
-
化简 sin(θ-5π)•cot( π 2 -θ)•cos(8π-θ) tan(3π-θ)•tan(θ- 3 2 π)•
-
化简：cot(θ+4π)•cos(θ+π)•sin2(θ+3π)tan(π+θ)•cos3(−π−θ)．
-
已知2cos 2 θ+5cosθ•sinθ-3sin 2 θ=0， θ∈( π 4 ， π 2 ) ，则tanθ=___
-
已知【2+tan(θ-π)】/【1-tan(2π-θ】=-4,求(sinθ-3cosθ)(cosθ-sinθ)的值
-
已知：tan(−5π−θ)•cos(θ−2π)•sin(−3π−θ)tan(7π2+θ)•sin(−4π+θ)•cot(