计算(3x^3y-x^2y+1/2xy)÷(-1/2xy)
2个回答
(3x^3y-x^2y+1/2xy)÷(-1/2xy)
=[x^2y(3x-1)+1/2xy]*(-2xy)
=-2x^3y^2(3x-1)-1
=2x^3y^2-6x^4y^2-1
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