1) A在x轴的负半轴上,n < 0
OA = -|5n,OA :OC = 5 :3,OC = -3n
设B(b,-3n),B在x轴上的垂足为E(b,0)
AB² = AE² + BE²
(-5n)² = (b - 5n)² + (-3n)²
b = 9n (在A左侧.舍去)
或b = n
B(n,-3n)
设D(0,d),OD = d,BD = √[(n - 0)² + (-3n - d)²] = √[n² + (3n + d)²]
OD = BD,d = -5n/3
D(0,-5n/3)
k = BD的斜率 = (-3n + 5n/3)/(n - 0) = -4/3