(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/(3-1)
=(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/2
=(3^4-1)(3^4+1)(3^8+1)(3^16+1)/2
=(3^8-1)(3^8+1)(3^16+1)/2
=(3^16-1)(3^16+1)/2
=(3^32-1)/2
(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
2个回答
相关问题
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(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
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计算：(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
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(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1=?
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计算：2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)+1
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（3+1/3）（3ˆ2+1/3ˆ2）（3ˆ4+1/3ˆ4）（3ˆ8+1/3ˆ8）（3ˆ16+1/3ˆ16）
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(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)怎么算啊
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计算(乘法公式)（3+1）（3^2+1）（3^4+1）（3^8+1）（3^16+1）
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3/2+3/4+3/8+1/16+1/32=
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2(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)(3^32+1)的个位数是什么?
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找规侓、①1/16,1/8,3/16,1/4,( ),( ).②1,3,4,7,11,( ),( ）.③8,4,2,1,