limAn/(1/n^2)=2/3 级数1/n^2收敛,所以原级数收敛.limsin(π/3^n)/(π/3^n)=1 级数π/3^n收敛.所以原级数收敛.lim[1/nn^(1/n)]/(1/n)=lim[1/n^(1/n)]=1 级数1/n发散....
limAn/(1/n^2)=2/3 级数1/n^2收敛,所以原级数收敛.limsin(π/3^n)/(π/3^n)=1 级数π/3^n收敛.所以原级数收敛.lim[1/nn^(1/n)]/(1/n)=lim[1/n^(1/n)]=1 级数1/n发散....