1.设f=ax+b;
a(ax+b)+b=aax+ab+b=4x-1;
a=2,b=-1/3
或a=-2,b=1
2。设t=x+1,则x=t-1
f(t)=2(t-1)²+1,
f(x-1)=2((x-1)-1)²+1=2x²-8x+9
3 0≤x²≤2
得
0≤|x|≤√2
1.设f=ax+b;
a(ax+b)+b=aax+ab+b=4x-1;
a=2,b=-1/3
或a=-2,b=1
2。设t=x+1,则x=t-1
f(t)=2(t-1)²+1,
f(x-1)=2((x-1)-1)²+1=2x²-8x+9
3 0≤x²≤2
得
0≤|x|≤√2