你化简到这里没错
后面是:sin2x-cos2x+1=√2(√2/2sin2x-√2/2cos2x)+1=√2(sin2xcosπ/4-cos2xsinπ/4)+1
=√2sin(2x-π/4)+1
即最大值,当sin(2x-π/4)=1时,原式=√2+1
最小值,当sin(2x-π/4)=-1时,原式=1-√2
注:√是根号
你化简到这里没错
后面是:sin2x-cos2x+1=√2(√2/2sin2x-√2/2cos2x)+1=√2(sin2xcosπ/4-cos2xsinπ/4)+1
=√2sin(2x-π/4)+1
即最大值,当sin(2x-π/4)=1时,原式=√2+1
最小值,当sin(2x-π/4)=-1时,原式=1-√2
注:√是根号