由题得:3x^2=1+x
带入原式
原式=3x^2(3x^2+4x)-11x^2-4x+2001
=(1+x)(1+x+4x)-11x^2-4x+2001
=1+6x+5x^2-11x^2-4x+2001
=-6x^2+2x+2002
=-2*3x^2+2x+2002
=-2(1+x)+2x+2002
=-2-2x+2x+2002
=2000
由题得:3x^2=1+x
带入原式
原式=3x^2(3x^2+4x)-11x^2-4x+2001
=(1+x)(1+x+4x)-11x^2-4x+2001
=1+6x+5x^2-11x^2-4x+2001
=-6x^2+2x+2002
=-2*3x^2+2x+2002
=-2(1+x)+2x+2002
=-2-2x+2x+2002
=2000