(1)2FeCI3 + 6Na + 6H2O == 2Fe(OH)3 + 6NaCI + 3H2
-----------6*23------------214----------------6
(2)6Na =====> (214+6-23*6) == 82
---6*23----------------------82
----xg-------------------(50-45.9)
(3)x == 6.9 g
(1)2FeCI3 + 6Na + 6H2O == 2Fe(OH)3 + 6NaCI + 3H2
-----------6*23------------214----------------6
(2)6Na =====> (214+6-23*6) == 82
---6*23----------------------82
----xg-------------------(50-45.9)
(3)x == 6.9 g