应该可以解函数方程,将P的数代人.
设批量N=1000,试求一次计数抽样方案(20,1)在p=0,0.01,0.05,0.10处的接收概率
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求y-(0.1y-0.1)/0.2=2-(0.01y+0.02)/0.05的解
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如果规定0.1=10/1=10的负一次方,0.01=100/1=10的负二次方,0.001=1000/1=10的负三次方
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规定:0.1=1/10=10^-1,0.01=1/100=10^-2,0.001=1/1000=10^-3