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原式=lim1/n[1/√(4-(1/n)^2)+1/√(4n^2-(2/n)^2)+...+1/√(4n^2-(n/n)^2)]
=1/√(4-x^2)在0到1上的积分
即arcsin(x/2)|0,1=pi/6
希望能帮助到您!
lim(n->无穷)(1/4n^2-2^2+2/4n^2-3^2+...+n-1/4n^2-n^2)
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