(1) 求m的值,并求f（x）的单调递增区间
f（x）=sin（2x+π/3)+sin（2x-π/3)+根号3*cos2x-m
=1/2*sin2x+√3/2*cos2x+1/2*sin2x-√3/2*cos2x+根号3*cos2x-m
=sin2x+根号3*cos2x-m
=2sin（2x+π/3)-m
∵f（x）的最大值为1 1
∴m=-9
f（x）的单调递增区间[kπ-5π/12,kπ+π/12]
(2)在△ABC中,角A,B,C的对边a,b,c,若f（B）=根号3-1,且根号3*a=b+c,试判断三角形的形状