1.y^2-10x^2+3x-4=(y^2-4)+( )=y^2-( )=3x-1-( ).

4个回答

  • 1.y^2-10x^2+3x-4=(y^2-4)+(3x-10x^2)=y^2-(10x^2-3x+4 )=3x-1-(10x^2-y^2+3)

    2.一个长方形的长为3x-2y,宽为2x+y,则它的周长为(10x-2y).

    3.计算(括号法则)

    (1)(ab+ac)-ab=ac

    (2)(3x^2-2xy-1/2x)-(2x^2-xy+x=x(x-y-3/2)

    (3)2(a-3b)+(-1/4a-5b)-3(1/4a-b)=a-8b

    (4)(1/2xy+y^2+1)-[x^2-(1/2xy-2y^2-1)-(y^2+xy)]=x(2y-x)

    4.先化简,再求值:1/15(-5x^2+15x-3)-(1/3x^2-1),其中x=-2

    =-58/15