损失的质量全部是 CO2气体
所以m(CO2) = 100 + 1-100/56 = 0.44g
(NH4)2CO3 + 2HCl == 2NH4Cl + H2O + CO2
96.44
m.0.44g
所以m = 96*0.44/44 = 0.96g
所以碳酸铵的质量分数 = 0.96/1 = 96%
损失的质量全部是 CO2气体
所以m(CO2) = 100 + 1-100/56 = 0.44g
(NH4)2CO3 + 2HCl == 2NH4Cl + H2O + CO2
96.44
m.0.44g
所以m = 96*0.44/44 = 0.96g
所以碳酸铵的质量分数 = 0.96/1 = 96%