(1)x/(x^2-3x+2)=x/(x-1)(x-2)=0,x=0
(2)(x-2)/(x^2-x-2)=(x-2)/(x-2)(x+1)=0,无解
(3)(x^2-16)/(x^2-3x-4)=(x+4)(x-4)/(x-4)(x+1)=0,x=-4
(1)x/(x^2-3x+2)=x/(x-1)(x-2)=0,x=0
(2)(x-2)/(x^2-x-2)=(x-2)/(x-2)(x+1)=0,无解
(3)(x^2-16)/(x^2-3x-4)=(x+4)(x-4)/(x-4)(x+1)=0,x=-4