1、90°,
在三角形ABC中,AB=AC,角BAC=90度,∠ABC=∠ACB=45°,
角DAE=角BAC,∴∠BAD=∠CAE,
AB=AC,AD=AE
△BAD≌△CAE
∠BAD=∠CAE=45°
角BCE=90
2、α+β=180
∠BAD=∠CAE,
AB=AC,AD=AE
△BAD≌△CAE
∠BAD=∠CAE
α+β=角BAC+角BCE=角BAC+∠BAD+∠ACB=180
3、α+β=180,同理证明△BAD≌△CAE即得
1、90°,
在三角形ABC中,AB=AC,角BAC=90度,∠ABC=∠ACB=45°,
角DAE=角BAC,∴∠BAD=∠CAE,
AB=AC,AD=AE
△BAD≌△CAE
∠BAD=∠CAE=45°
角BCE=90
2、α+β=180
∠BAD=∠CAE,
AB=AC,AD=AE
△BAD≌△CAE
∠BAD=∠CAE
α+β=角BAC+角BCE=角BAC+∠BAD+∠ACB=180
3、α+β=180,同理证明△BAD≌△CAE即得