解设x/2=y/3=z/4=k
即x=2k,y=3k,z=4k
故
x+y+3z/3x+2y
=（2k+3k+3×4k）/（3×2k+2×3k）
=17k/12k
=17/12
已知x/2=y/3=z/4不等于0,求x+y+3z/3x+2y的值
3个回答
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