√3sinx/2+cosx/2=y/cosx/2=1/cosx/2
则√3sinx/2cosx/2+cos²x/2=1
√3/2sinx+1/2(cosx+1)=1
sin(x+π/6)=1/2,cos(x+π/6)=±√3/2
cos(2π/3-2x)=sin(2x-π/6)=sin(2x+π/3-π/2)
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√3sinx/2+cosx/2=y/cosx/2=1/cosx/2
则√3sinx/2cosx/2+cos²x/2=1
√3/2sinx+1/2(cosx+1)=1
sin(x+π/6)=1/2,cos(x+π/6)=±√3/2
cos(2π/3-2x)=sin(2x-π/6)=sin(2x+π/3-π/2)
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