已知抛物线y=x^2+2(m-1)x+2m-3,

3个回答

  • (1) x1 < 0,x2 < 0,x1 + x2 = -2(m-1) < 0,m > 1

    x1*x2 > 0,x1*x2 = 2m-3 > 0,m > 3/2

    即m > 3/2

    (2) 顶点到x轴的距离等于2m-3

    y=x^2+2(m-1)x+2m-3 = (x + 1)(x + 2m -3)

    x1 = -1,x2 = 3 - 2m

    AB = |x2 - x1| = |4-2m|

    2m -3 = |4 - 2m|

    (a) 3/2 < m < 2:

    2m - 3 = 4 - 2m

    m = 7/4

    y = x^2 +3x/2 + 1/2

    (b) m ≥ 2

    2m -3 = 2m -4,不成立