Question

0.05摩尔每升的醋酸钠溶液的PH值为多少

Answer 1

0.05 mol/L的醋酸钠溶液.

[OH-] = √Kw / Ka * c

=√ (10^-14) / (1.8*10^-5) * 0.05

=5.3*10^-6 (mol/L)

PH = 14 - POH = 14 - 5.28 = 8.72