Question

急求一个关于洗车仿真的编程代码,题目如下要用C语言做.

Answer 1

#include

#include

#include

#include

#define QUENELEN 6

#define QUENENUM 3

#define MAXTIME 360

struct cCar

{

int num;

int waitTime;

int serverTime;

int arriveTime;

int leaveTime;

int quene;

struct cCar * next;

} ;

struct cQuene

{

x05int quene;

int queneNum;

int num[QUENELEN];

int waitTime[QUENELEN];

int serverTime[QUENELEN];

};

void initCar(struct cCar * s)

{

s->num = 0;

s->waitTime = 0;

s->serverTime = 0;

s->arriveTime = 0;

s->leaveTime = 0;

s->quene = 0;

s->next = NULL;

}

void printQuene(struct cQuene * s)

{

x05int i;

x05printf("%dt%dn",s->queneNum ,s->quene );

x05for(i=0;iserverTime [i]);

x05printf("n");

x05for(i=0;iwaitTime [i]);

x05printf("n");

x05for(i=0;inum [i]);

x05printf("n");

x05printf("n");

}

void initQuene(struct cQuene * s,int n)

{

int i;

x05s->quene = n;

s->queneNum = 0;

for(i = 0; i < QUENELEN; i++)

{

s->num[i] = 0;

s->waitTime[i] = 0;

s->serverTime[i] = 0;

}

}

int curTime=0,Num=1;

struct cCar firstCar;

struct cQuene Quene[QUENENUM];

void initQuene()

{

x05int i;

x05for(i=0; iserverTime[i];

return count;

}

void updataQuene(struct cQuene * s)

{

int i;

x05struct cCar *p = &firstCar;

s->serverTime[0]--; //洗车时间减1

if(s->serverTime[0] next)

x05x05x05{

x05x05x05x05if(p->num == s->num [0]) break;

x05x05x05x05p = p ->next ;

x05x05x05}

x05x05}

x05x05if(p)

x05x05{

x05x05x05p->leaveTime = curTime+1; //记录离开时间

x05x05x05p->waitTime = s->waitTime[0]; //记录等待时间

x05x05}

x05x05else printf("没有找到编号为%d的车",s->num [0]);

for(i = 0; i < s->queneNum; i++) //队列移动

{

s->num[i] = s->num[i+1];

s->waitTime[i] = s->waitTime[i+1];

s->serverTime[i] = s->serverTime[i+1];

}

s->num[i] = 0;

s->waitTime[i] = 0;

s->serverTime[i] = 0;

if(s->queneNum>0) s->queneNum--; //队列数减1

}

x05for(i = 1; i queneNum; i++) s->waitTime[i]++; //等待时间加1

}

void updataQuene()

{

x05int i;

x05for(i=0;i 0) updataQuene(&Quene[i]);

x05x05//printQuene(&Quene[i]);

x05}

}

void addCar()

{

x05const int serverTime[3] = {10,15,25};

x05struct cCar * p = &firstCar;

x05int i,j,queneWait[QUENENUM],index[QUENENUM],minpos,tmp;

x05while(p->next) p = p ->next ; //最后一条记录

x05p->next = (struct cCar *)malloc(sizeof(struct cCar)); //添加新车

x05p = p ->next;

x05p->arriveTime = curTime; //车到达时间

x05p->num = Num++; //到达序号

x05p->next = NULL;

x05p->serverTime = serverTime[rand() % 3]; //服务时间

x05p->leaveTime = curTime;

x05p->waitTime = 0;

x05p->quene = -1;

x05

x05for(i=0; iquene = index[i];

x05x05x05x05break;

x05x05x05}

x05x05}

x05}

}

void main()

{

x05int i,num=0,count=0;

x05int wait = rand() % 30;

x05struct cCar * p = &firstCar,*p2;

x05srand(time(NULL));

x05initQuene();

x05while(curTimenext ;

x05printf("编号t队列号t到达t离开t服务t等待n");

x05while(p)

x05{

x05x05printf("%dt%dt%dt%dt%dt%dn",p->num ,p->quene ,p->arriveTime ,p->leaveTime ,p->serverTime ,p->waitTime );

x05x05if( p->arriveTime != p->leaveTime)

x05x05{

x05x05x05num ++;

x05x05x05count += p->waitTime;

x05x05}

x05x05p = p->next ;

x05}

x05printf("平均等待时间%fn",(double) count / (num+1));

x05p = firstCar.next ;

x05while(p )//释放空间

x05{

x05x05p2 = p;

x05x05p = p->next ;

x05x05free(p2);

x05}

}