如图所示,平面直角坐标系中,四边形OABC为矩形,点A、B的坐标分别为(4,0), (4,3),动点M、N分别

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  • 1、P(1,9/4)利用AM/OA=(4-1)/4=3/4PM/OC=3/4 得PM=3/4×OC=3/4×3=9/42、CN=BC-BN=4-t利用AM/OA=PM/OC(4-t)/4=PM/3PM=3(4-t)/4=3-3t/4那么△NPC的高=OC-PM=3-3+3t/4=3t/4∴S△NPC=1/2CN×高=1/2(4-t)×3t/4=(3/...