原式=[1/(x+1)+(x-1)^2/(x+1)(x-1)]×[(x+1)/(x-1)]
=[1/(x+1)+(x-1)/(x+1)]×[(x+1)/(x-1)]
=x/(x+1)×[(x+1)/(x-1)]
=x/(x-1)
数学题化简再求值化简再求值那是x² ,不要看错了
原式=[1/(x+1)+(x-1)^2/(x+1)(x-1)]×[(x+1)/(x-1)]
=[1/(x+1)+(x-1)/(x+1)]×[(x+1)/(x-1)]
=x/(x+1)×[(x+1)/(x-1)]
=x/(x-1)