ds/dt=[cost(1+cost)-(1+sint)(-sint)]/(1+cost)²
=(cost+cos²t+sint+sin²t)/(1+cost)²
=(cost+sint+1)/(1+cost)²
怎么求s=(1+sint)/(1+cost)的导数?
2个回答
相关问题
-
已知sint+cost=1，设s=cost+isint，求f（s）=1+s+s2+…sn．
-
关于导数的问题dy/dx=[a(1-cot)]'/[a(t-sint)]'=asint/a(1-cost)=sint/1
-
求函数f(t)=√[(cost-1)^2+(sint+1)^2]+√[(cost+1/5)^2+sint-7/5)^2]
-
t趋于0时lim(sint+cost-1)/t=lim(cost-sint)=1)
-
(cost-sint)/(sint-cost) 的结果不知道等不等于 -(sint-cost)/(sint-cost)也
-
∫cost/(sint^2) dt =∫dsint/sint^2 =-1/sint + C
-
∫sint*sinwtdt怎么求积分?还有∫cost*coswtdt?
-
求方程x=a(t+sint),y=a(1+cost)确定的参数式函数的导数.a为常数
-
因为t趋于0时,lim(sint cost-1)/t=lim(cost-sint)=1这是为什么
-
1/(cost+sint) 最小值