Question

化学:由有机物ABC三种同分异构体组成的混合物M,其蒸气对氢气的相对密度为30.

Answer 1

混合物M,其蒸气对氢气的相对密度为30

M混=2*30=60 n混=1.8/60=0.03mol

硫酸增重2.16g m(H2O)=2.16g 剩下气体2016毫升(标况下) n(CO2)=2.016/22.4=0.09mol

n(H2O)=2.16/18=0.12mol m(H)=0.24g m(C)=0.09*12=1.08g m(O)=1.8-1.08-0.24=0.48g

n(C)=0.09mol n(H)=0.12*2=0.24mol n(O)=0.48/16=0.03mol

所以实验式为：C3H8O

所以A：CH3CH(OH)CH3 B;CH3CH2CH2OH C;CH3CH2-O-CH3